(2^x)*(3^2x)=17

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Solution for (2^x)*(3^2x)=17 equation: 



(2^x)(3^2x)=17

We move all terms to the left:

(2^x)(3^2x)-(17)=0

We move all terms containing x to the left, all other terms to the right

2^x3^2x=17

x=17/1

x=17

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